Any One Good At Maths..I Need Help!!!

[scoosh-89]

Im currently studing for my HNC exam which is in two weeks. Came accross this question and need help re-arranging the equation.

The Equation.

Qm = 60.p.Cd.A2 [2.AP/p(1-(A2/A1)2)] (0.5)

I need to solve for Cd and im stugling.

so far i have

Qm
[2.AP/p(1-(A2/A1)2)] (0.5) = 60.p.Cd.A2

Where do i go from here?

Can anyone shed some light? PLEASE.

[yorkie_chris]

Is it just Cd which is unknown or do you just have to rearrange for Cd

[scoosh-89]

I have to re arrange so Cd = ??? and then solve Cd using the equation. i have all the values for the other variables.

[appollo1]

1+1=2
2+2=4
3+3=6

etc etc etc

[sloppy joe]

"Qm = 60.p.Cd.A2 [2.AP/p(1-(A2/A1)2)] (0.5)"

'.' is multiplied by? and brackets adjacent to a term also represent the same?

if so, can be re-ordered as:

Qm = Cd.(60.p.A2 [2.AP/p(1-(A2/A1)2)] (0.5))

so, can divide both sides by (60.p.A2 [2.AP/p(1-(A2/A1)2)] (0.5)), which gives:

Qm / (60.p.A2 [2.AP/p(1-(A2/A1)2)] (0.5)) = Cd

Unless I am misunderstanding your terminology?

Essentially, if all terms are being multiplied together, you can divide both sides by everything apart from Cd, leaving Cd on its own.

[TazDaz]

Use brackets loads! :)

[kellyjo]

Not certain but ...

Qm
[2.AP/p(1-(A2/A1)2)] (0.5)60.p.A2 = Cd

[yorkie_chris]

"Qm = 60.p.Cd.A2 [2.AP/p(1-(A2/A1)2)] (0.5)"

'.' is multiplied by? and brackets adjacent to a term also represent the same?

if so, can be re-ordered as:

Qm = Cd.(60.p.A2 [2.AP/p(1-(A2/A1)2)] (0.5))

so, can divide both sides by (60.p.A2 [2.AP/p(1-(A2/A1)2)] (0.5)), which gives:

Qm / (60.p.A2 [2.AP/p(1-(A2/A1)2)] (0.5)) = Cd

Unless I am misunderstanding your terminology?

Essentially, if all terms are being multiplied together, you can divide both sides by everything apart from Cd, leaving Cd on its own.

That :)

[scoosh-89]

"Qm = 60.p.Cd.A2 [2.AP/p(1-(A2/A1)2)] (0.5)"

'.' is multiplied by? and brackets adjacent to a term also represent the same?

if so, can be re-ordered as:

Qm = Cd.(60.p.A2 [2.AP/p(1-(A2/A1)2)] (0.5))

so, can divide both sides by (60.p.A2 [2.AP/p(1-(A2/A1)2)] (0.5)), which gives:

Qm / (60.p.A2 [2.AP/p(1-(A2/A1)2)] (0.5)) = Cd

Unless I am misunderstanding your terminology?

Essentially, if all terms are being multiplied together, you can divide both sides by everything apart from Cd, leaving Cd on its own.

('.' is multiplied by) CORRECT.

(0.5) is to the power of so i will have to square the other side to clear this.

Will give it ago and see what answer i get as i know roughly what the answer should be.

Cheers.

[yorkie_chris]

Is Cd within the sqrt bit or is it sqrt[2.AP/p(1-(A2/A1)2)]

[sloppy joe]

(0.5) is to the power of so i will have to square the other side to clear this.

Yep, do that first, then you will be able to divide out the rest.

Good luck with the exam.

[Stuuk1]

All I can gather from this post is that you are trying to work out how much a cd costs?

Why dont you just look on www.play.com

No thanks required.

[sloppy joe]

Is Cd within the sqrt bit or is it sqrt[2.AP/p(1-(A2/A1)2)]

Oops, just seen yc's bit above - and that would make a difference.

[Specialone]

All I can gather from this post is that you are trying to work out how much a cd costs?

Why dont you just look on www.play.com (http://www.play.com)

No thanks required.


:)

[timwilky]

Can somebody write that initial equation so that an old git who did his maths 30 years ago can understand it.

I used to be a whizz at second order differential equations, now I cannot remember what one was.


Well off to the place where I always did my revision (The pub)

[scoosh-89]

Can somebody write that initial equation so that an old git who did his maths 30 years ago can understand it.

I used to be a whizz at second order differential equations, now I cannot remember what one was.


Well off to the place where I always did my revision (The pub)

Wish i could go to the pub but my job depends on this exam.

Thanks for everyone input as i think iv got the correct answer.

[sloppy joe]

Well off to the place where I always did my revision (The pub)

Pint of Carling would be nice. Oh, and some crisps. Cheers.

Wish i could go to the pub but my job depends on this exam.

Know the feeling, have had work exams every 6 months for the last 2 1/2 years, it can be a drag. However, the beer after you pass will taste damn good.

[scoosh-89]

Pint of Carling would be nice. Oh, and some crisps. Cheers.

Thanks for rubbing it in lol



Know the feeling, have had work exams every 6 months for the last 2 1/2 years, it can be a drag. However, the beer after you pass will taste damn good.

Well im heading out the following day so im hoping your right. Need to wait a week to find out my result though.

[Sally]

Thanks for rubbing it in lol





Well im heading out the following day so im hoping your right. Need to wait a week to find out my result though.

Yeah I had to cancel going to last years Rockness to revise for a resit :(

Scrub going out the following day, you should be going straight to the pub :)

[timwilky]

I was lucky to have a good maths lecturer who one chrismas told us to sod off back to the pub.

Coincident then that 20 years later he supervised my then boss get his Ph.D in Mathematics for research work on Steiner Triple Series.

[scoosh-89]

Yeah I had to cancel going to last years Rockness to revise for a resit :(

Scrub going out the following day, you should be going straight to the pub :)

I will be, im going to glasgow to see Kevin bridges at night and will be in the pub most of the day. :D

[BigBaddad]

42

[Bluepete]

42

That's a Deep Thought!

Pete ;)

[ArtyLady]

42

I wish I was :smt061

[Bluefish]

i am at the mo. anyhow nobody uses cd's these days it's all downloads, get with it.