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So Jane rides 15 miles by motorway to work at an average of 60mph and reaches work in 15mins.
The next day she has to do some filtering due to traffic, and travels at 20mph before returning to 60mph, reaching work in 21mins.
Over what distance was she filtering?
(please assume that all speed changes were instant, no smart arses! :p )
Now I know what the answer is, but through trial and error. What I want to know is, is it possible to solve this through algebra and if so, can someone smarter than I demonstrate how? My GCSE maths fails me and I'm losing sleep over it. Cheers!
Mrs DJ Fridge
10-02-14, 10:28 PM
DJ is working on it, he has just one off in search of a pen and paper
Fallout
10-02-14, 11:04 PM
I tried to work that **** out and failed. Something to do with simultaneous equations but the units throw me. It's annoying because I write algorithms for complex 3d principles every day but can't do a feckin' GCSE question!
DJFridge
10-02-14, 11:09 PM
Grrr, I now have a page of cr@p equations with an equation which works but I can't work out how to rearrange it to make the filtering distance the answer. Which probably means it's wrong and only works with those exact figures. I got an A in O Level maths and my brain appears to have forgotten most of it!
Paul the 6th
10-02-14, 11:35 PM
Why is this the last thing I've read before bed.
a1istair
11-02-14, 01:11 AM
Choose compatible units to solve the problem:
miles, hours, miles per hour
Original journey:
d = s x t
15 miles = 60 mph x 15/60 h
New journey:
d = s1 x t1 + s2 x t2
15 miles = 20 mph x t1 + 60 mph X t2
Total time is 21/60 h:
t1 + t2 = 21/60 h
So:
t2 = 21/60 h - t1
Combine these 2 equations:
15 miles = 20 mph x t1 + 60 mph X (21/60 h - t1)
Multiply the brackets:
15 miles = 20 mph x t1 + 21 miles - t1 x 60 mph
Combine the t1 components:
15 miles = 21 miles - t1 x 40 mph
Combine the miles components:
6 miles = t1 x 40mph
So we can now get all unknowns:
t1 = 6 miles / 40 mph = 6/40 h = 9 mins
t2 = 21 - 9 = 12 mins
d1 = 9/60 h x 20 mph = 3 miles
d2 = 15 miles - 3 miles = 12 miles
Thanks a1istair! Once I've fully woken up I'll have a proper read to soak it all in! Cheers :)
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I just thought it's going to take her 3mins at 20mph to go the same distance as she would at 60 mph.
So you take away one min then add three. Do that three times then you get 21mins
So 3mins at 20 mph,20mph = 1/3 mile per min. That's 1miles in total
Who needs equations! They make it more complicated
I suck at maths. This kind of thing just makes my mind go blank.
I just thought it's going to take her 3mins at 20mph to go the same distance as she would at 60 mph.
So you take away one min then add three. Do that three times then you get 21mins
So 3mins at 20 mph,20mph = 1/3 mile per min. That's 1miles in total
Who needs equations! They make it more complicated
The point is knowing how to apply it to the same question with different figures. Yes I worked it out in my head too, but that's because they gave us nice figures of 20 and 60. If they gave you 19 and 61 then it's not so easy.
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Littlepeahead
11-02-14, 09:23 AM
In reality though wouldn't you be working out how long it took her to get to A&E in the ambulance after some dippy driver didn't check their mirrors and pulled out in front of her while she was filtering?
yorkie_chris
11-02-14, 10:57 AM
20mph get the fookin hammer down you poof... :mrgreen:
keith_d
11-02-14, 01:24 PM
When she filtered the journey took 6 minutes longer (21 -15 minutes) than usual.
However, she filtered at exactly one third of her normal speed. Therefore she filtered for a total of 9 minutes.
Distance travelled = 20 * 9 / 60 = 3 miles.
She needs to learn how to ride in traffic, then go to night classes to do math ;)
ClunkintheUK
11-02-14, 04:36 PM
I didn;t do very well at figuring it out in my head, but took me 5 minutes to figure out the formula. I hate using MPH, or anything per hour for these calculations, always get my units in a fuddle then.
SvNewbie
11-02-14, 04:49 PM
Yeah, having to put the time in as 21/60 ****ed me over the first time I tried.
LewSpeight
11-02-14, 05:29 PM
Completely kinda off topic but i've got some brand new unused GCSE revision books if they're any use to anyone? Cover the postage and they're yours. (OP'er gets first dibs)
yorkie_chris
11-02-14, 08:04 PM
Having met lewis I can vouch for the fact that they're almost certainly unread :mrgreen:
(I say unread, they might have been chewed a bit though)
Nobbylad
11-02-14, 08:16 PM
Is Jane fit or not, regardless of her riding ability?
LewSpeight
11-02-14, 08:41 PM
Having met lewis I can vouch for the fact that they're almost certainly unread :mrgreen:
(I say unread, they might have been chewed a bit though)
:smt062
DJFridge
11-02-14, 09:10 PM
Is Jane fit or not, regardless of her riding ability?
A far more important question;)
Matt-EUC
11-02-14, 11:54 PM
I agree, I'd like to know the answer to this as well.
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