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#1 |
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How embarassing.
Ok, so I'm shipping some stuff by sea and the freight co charge by cubic metres. Below are the dimensions of each item as given to me by the supplier's warehouse. I will have 2 of each: Length: 0.32m Height: 0.20m Width: 0.28m Length: 0.30m Height: 0.27m Width: 0.27m My math isn't what it used to be, apparently. Last edited by hongman; 05-01-11 at 06:03 PM. |
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#3 |
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You multiply the length by the width by the height of each item to get the volumne.Then add the results together to get the total.
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#4 |
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Thats what I did but kept getting negative values.
Site is playing up for me, but I'll try after dinner! Thanks Regards Stupid. |
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#5 |
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Box 1 is 0.1792
Box 2 is 0.2187 If you have two of each you double those numbers and add the result together for the total.
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#6 |
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1.792m(cubed) + 2.187m(cubed)
3.979m(cubed) I worked in cm for the values you gave me inm(cubed), to find a value in cm(cubed), then to get back to m(cubed) you have to divide by (100x100=10000). Its because the values are >1, they make funny figures, so you have to go up from m(cubed) to cm(cubed) then divide back down. I think thats right, but wait for someone more knowledgable than me to tell you. |
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#7 |
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I think I am possibly wrong looking at BB's answer!
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#8 |
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Surely volume is simply length x breadth x height
Therefore box 1: 0.32 x 0.2 x 0.28 = 0.01792m^3 box 2: 0.3 x 0.27 x 0.27 = 0.02187m^3 Hopefully we agree on that... seeing as im studying engineering and hopefully not making schoolboy errors! Yet i find it interesting that there are 3 sets of answers, all the same numbers, but factors of 10 different!
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#9 |
Captain Awesome
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Are you shipping them all in separate packages? Placing them all in the same box will leave room left over so the total will be slightly more than the individual boxes combined
That said, the volume of the first item is: 0.32 x 0.20 x 0.28 = 0.01792 cubic metres Item two: 0.30 x 0.27 x 0.27 = 0.02187 cubic metres Double the values for two of the same item, add the results for the total simples...
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#10 | |
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![]() Quote:
Box 2 = 0.3m*0.27m*0.27m = 0.02187m^3 2 Of each box = (2*0.01792)+(2*0.02187) = 0.08m^3 (or 0.07958 if you want to be accurate). Edit: Factors of 10 catch loads of people out. Last edited by MisterTommyH; 05-01-11 at 07:05 PM. |
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