OMO. % by volume question - SV650.org

Bibio · 20-09-20, 02:13 PM

i'm usually not to bad when it comes to basic maths but i have a question for the more knowledgable amongst us as i think i'm wrong with my calculations.

it goes like this. if i have a liquid (coal tar solution) that is 200ml @ 40% and pour it into another solution (soap recipe) that is 1800ml to make a final solution of 2000ml would i end up with 4% or 0.4% or something else (coal tar) in the 2000ml?

my workings were
2000 / 200 = 10 then 40 / 10 = 4?
or
2000 / 40% = 0.4?
or
your calculations???

Ruffy · 20-09-20, 02:26 PM

By my reckoning, I think you end up with 4% solution.

Working:
200ml @ 40% = 200 x 0.4 = 80ml of the "pure" substance
=> when diluted, 80ml is in 2000ml total, so
80 / 2000 = 0.04 = 4%

(This is assuming it's just basic mixing and there's no chemical jiggery-pokery etc. when you mix the two solutions.)

Bibio · 20-09-20, 02:32 PM

my assumption was 4%. i like the way you broke down to the 'pure' substance. i never thought of that.

johnnyrod · 20-09-20, 08:42 PM

Yes and yes, gold star both of you

SV650rules · 21-09-20, 10:51 AM

Quote:

Originally Posted by johnnyrod

Yes and yes, gold star both of you

Spot on - and extra points for showing workings

20-09-20, 02:13 PM	#1
Bibio Member Mega Poster Join Date: Jul 2008 Location: here as devil's advocate Posts: 11,540	OMO. % by volume question i'm usually not to bad when it comes to basic maths but i have a question for the more knowledgable amongst us as i think i'm wrong with my calculations. it goes like this. if i have a liquid (coal tar solution) that is 200ml @ 40% and pour it into another solution (soap recipe) that is 1800ml to make a final solution of 2000ml would i end up with 4% or 0.4% or something else (coal tar) in the 2000ml? my workings were 2000 / 200 = 10 then 40 / 10 = 4? or 2000 / 40% = 0.4? or your calculations???

20-09-20, 02:26 PM	#2
Ruffy Member Join Date: Aug 2007 Location: nr. Ashby-de-la-Zouch Posts: 321	Re: OMO. % by volume question By my reckoning, I think you end up with 4% solution. Working: 200ml @ 40% = 200 x 0.4 = 80ml of the "pure" substance => when diluted, 80ml is in 2000ml total, so 80 / 2000 = 0.04 = 4% (This is assuming it's just basic mixing and there's no chemical jiggery-pokery etc. when you mix the two solutions.) __________________ Spannering the wife's SV650S K5 pointy in Black, and son's SV650 X curvy in Blue. RIP SV650 X curvy, crashed and written off December 2019. I'm (procrastinating about) fixing up an old Yamaha FZ600 to get myself fully back on the road.

20-09-20, 02:32 PM	#3
Bibio Member Mega Poster Join Date: Jul 2008 Location: here as devil's advocate Posts: 11,540	Re: OMO. % by volume question my assumption was 4%. i like the way you broke down to the 'pure' substance. i never thought of that.

20-09-20, 08:42 PM	#4
johnnyrod Member Mega Poster Join Date: Jul 2003 Location: Doncaster, oop norf Posts: 2,122	Re: OMO. % by volume question Yes and yes, gold star both of you

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