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12-09-06, 03:43 PM | #11 | |
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If the LED is rated at 3.3v and you're only supplying it from two AA cells, there's little point in a resistor. Other than that little factet, we both appear to have the same outcome (note: it's not the 1st formula - the one you quoted - that's right, it's the 2nd) Edit: Also, since there will be a resistor to drop from 12v to the LED input voltage, you could use both my first & last formulae to work out the parallel resistance required. |
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12-09-06, 03:59 PM | #12 | |
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I've been writing very badly all the way through this, I just realised... Left out bits I meant to, which probably makes it confused nonsense in places. If I add in about 20 "in a bike application" and "according to the links" it'd work, I think
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12-09-06, 03:59 PM | #13 | ||||
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Markyboy wrote
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12-09-06, 03:59 PM | #14 |
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I'm no expert and a lot of people on here know there stuff about electric and I'll pull my head in if if got the wrong end of the stick....
would these not work a 12v resistor |
12-09-06, 04:07 PM | #15 | |
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DoubleD, brown blue black gold. That's a 16Ohm resistor. Depends entirely on what you wanted to use it for. |
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12-09-06, 04:08 PM | #16 |
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Dunno, they look suspiciously wee though. I think those are intended as series resistors with a stand-alone LED? Could be wrong. But I'd be really surprised if those are going to be able to deal with the job, they want to be 10W or more really I reckon. (rule of thumb, that)
http://www.ultraleds.co.uk/product_i...075c5174cced41 This'd work. Also, be ridiculously expensive
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12-09-06, 04:08 PM | #17 | |
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12-09-06, 04:19 PM | #18 | |
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12-09-06, 04:26 PM | #19 |
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