Quote:
|
Originally Posted by furrybean
It aint cubed on the assignment sheet but do u reckon it might me wrong.
I got to this
sin3θ = 3sinθ - 4sin3θ
substituting jA for θ gives
sin3jA = 3sinjA - 4(sin3jA)
since sinjA = jsinhA
jsinh3A = 3jsinhA - 4(jsinh3A)
jsinh3A = 3jsinhA - 4jsinh3A
just that negative sign!!!
|
Personally yes I think the assignment sheet is wrong, won't be the first time! or even the last!
Don't sweat over it anymore