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flymo · 16-05-12, 08:53 PM

250 ohms in total

the formulas above are good, simple way though when the numbers are easy enough. Two resistors of equal value in parallel - halves the resistance. So R4 and R5 can be replaced by 50ohms, then add R3 making 100 ohms. Same again between R2 and (R3+R4+R5 combo) is 50 ohms.

Then add the resistances in series = 100 + 50 + 100 = 250 ohms.

16-05-12, 08:53 PM	#3
flymo Member Mega Poster Join Date: Jan 2008 Location: North West Posts: 3,124	Re: electronics (maths) question 250 ohms in total the formulas above are good, simple way though when the numbers are easy enough. Two resistors of equal value in parallel - halves the resistance. So R4 and R5 can be replaced by 50ohms, then add R3 making 100 ohms. Same again between R2 and (R3+R4+R5 combo) is 50 ohms. Then add the resistances in series = 100 + 50 + 100 = 250 ohms. Last edited by flymo; 16-05-12 at 08:56 PM.