 |
 |
Idle Banter For non SV and non bike related chat (and the odd bit of humour - but if any post isn't suitable it'll get deleted real quick). There's also a "U" rating so please respect this. Newbies can also say "hello" here too. |
 |
|
|
Thread Tools |
15-01-07, 09:42 PM
|
#11 | |
|
Guest
Posts: n/a
|
Re: Hyperbolic Functions
Quote:
|
|
|
|
15-01-07, 09:45 PM
|
#12 |
|
Guest
Posts: n/a
|
It aint cubed on the assignment sheet but do u reckon it might me wrong.
I got to this sin3θ = 3sinθ - 4sin3θ substituting jA for θ gives sin3jA = 3sinjA - 4(sin3jA) since sinjA = jsinhA jsinh3A = 3jsinhA - 4(jsinh3A) jsinh3A = 3jsinhA - 4jsinh3A just that negative sign!!! |
|
|
|
15-01-07, 09:48 PM
|
#13 | |
|
Guest
Posts: n/a
|
Quote:
 Don't sweat over it anymore |
|
|
|
|
15-01-07, 09:50 PM
|
#14 |
|
Guest
Posts: n/a
|
well cheers for the help. Can you go that with the 4sin3jA and put the 4 like 4(sin3jA) so it goes to 4jsinh3A
|
|
|
|
15-01-07, 10:07 PM
|
#15 | ||
|
Guest
Posts: n/a
|
Quote:
Quote:
then divide thru by j sinh3A = 3sinhA - 4sinh3A but like you say that's not what is on your sheet |
||
|
|
|
15-01-07, 10:13 PM
|
#16 |
|
Guest
Posts: n/a
|
Ok well cheers for the help matey
|
|
|
|
15-01-07, 10:36 PM
|
#17 |
|
Guest
Posts: n/a
|
The proof is in the text book, which have just dug out and blown the cobwebs off
 
|
|
|
|
15-01-07, 10:42 PM
|
#18 |
|
Guest
Posts: n/a
|
Minter, well I now know they dont make up the qu themselves.
What book is that? Cheers |
|
|
|
15-01-07, 10:52 PM
|
#19 | |
|
Guest
Posts: n/a
|
Quote:
what are you studying? 
|
|
|
|
|
16-01-07, 12:00 AM
|
#20 |
|
Guest
Posts: n/a
|
The answer is
42 |
|
|
|
|
|
