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#21 |
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Last edited by stuartyboy; 28-05-07 at 08:39 AM. |
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#22 | |||
Captain Awesome
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the reason i asked for units is that you didn't state what units you were using for the diameter in this formula: not because i didn't understand what you were suggesting i've no idea how much you've done regarding physics but they taught us back at GCSE that to not state units is about the most basic mistake you can make then there's the fact that neither of your formulae hold up to scrutiny mph * gear ratio * 336 gives a result of 17912 for 30mph in second gear, seeing as you've not stated whether "rpm" means engine rpm or rear wheel rpm i can only assume your diameter measurement is one of the following in the case of you meaning engine rpm, diameter = 17912 / 5000 = 3.58units or if you meant wheel rpm, diameter = 17912 / 407 = 44units i suppose 44cm is closest ![]() as for your other formula: Quote:
as before you should be multiplying by the inverse of the gear ratio, it looks like you've got a bit jumbled up rearranging your multipliers, dividers and brackets Quote:
go back, check your formulae, show your working 4/10 - must try harder ![]()
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#23 |
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Last edited by stuartyboy; 28-05-07 at 08:39 AM. |
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#24 | |
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when you've finished picking up on irrelevant minor errors, could you explain the fundamental errors in your formulae and why they don't show anything like what is observed in the real world ta ![]()
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#25 |
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God I love maths.
Matt |
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#26 |
Captain Awesome
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chemistry is physics with no maths
maths is physics with no point ![]()
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#27 | ||
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a simple units calculation means that your formula is effectively [(distance in miles / time in hours) * unitless * unitless] / diameter in ? = 1 / time in minutes rpm is measured in revolutions per minute, ie: a unitless number per given time, in this case one minute miles per hour is distance per given time, in this case one hour therefore your diameter is in the correct units (a distance as opposed to unitless or inverse time) but you've mixed miles, hours and minutes in such a way that it makes no sense and produces incorrect results, your proportionality constant of 336 seems arbitrary, so i would look there for your error first QFE: Quote:
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#28 |
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I love maths too. Ten years ago I'd have been in the middle of this. But that's long enough my for the knowledge gained in doing my A levels in maths to have eporated. I watch numb3rs despite the really awful tag line "we all use math everyday".
Physics is theoretical engineering. Ie those that can do, those that can't talk about it. ![]() |
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#29 |
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I actually wrote a little speed/gear ratio calculator. I can email you the executable if you want?
![]() It allows the user to enter in different sprocket combinations and revvs to ascertain what the speed would be in each gear. You can even save the results to a text file ![]() I see wheel circumference has been discussed. This is an important factor and the only way is to measure it, there is no point trying to guesstimate from the code on the side as 2 tyres with the same code 160/55/17 could well be different ... also as the tyre wears its circumference lessens ... My rear tyre was 198cm circumference. The program allows the user to configure this. edit:- here you go, I uploaded it to a share site where you can download it!! ![]() http://www.sharebigfile.com/file/176...SV650-exe.html If it isn't on your machine already, you might need COMDLG32.OCX for it to work, this can be downloaded directly from Microsoft ![]() http://activex.microsoft.com/controls/vb5/comdlg32.cab Last edited by Blue_SV650S; 27-05-07 at 12:19 PM. |
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#30 | |
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have you seen this: http://blogs.msdn.com/coding4fun/arc...8/1709215.aspx
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