maxing out

[northwind]

There's always something faster... The faired SV's a little overgeared IMO, you're not the first to find they can't rev it out. Mine has something like 15-20bhp more than stock once you get near the redline (it makes around 80 at peak compared to 68 or so standard, but also doesn't fall off after peak as hard as stock does), and it still takes a fair old time to reach the limiter with the standard gearing. The actual difference in speed isn't huge though.

Another thing to note is that hitting the limiter in top is quite alarming when it happens, I can't recommend it I thought I'd blown it up

I've got a K3 and hit the rev limiter at an indicated 133. I was so tucked in you couldn't imagine-almost part of the bike. Believe it or not it was the first time I'd hit the limiter! I don't make a habit of it.

I wouldn't worry about the 9000 rev thing-the wind was probably against you or something. Do you eat a lot of pies?

As far as outgrowing the SV, well I doubt you have, especially considering you only passed your test IN APRIL! DOH! (See first post)

Originally Posted by northwind

Another thing to note is that hitting the limiter in top is quite alarming when it happens, I can't recommend it I thought I'd blown it up

He he. I did write something like that in my post but deleted it. Something went poop poop when I done it and it wasn't the bike!

Thanks for all the comments...

As far as outgrowing the SV, well I doubt you have, especially considering you only passed your test IN APRIL! DOH!

Yes i know i only passed my test in april but have been riding bikes for 15 years and its not a case of out growing the bike....

Gear it down... You're basically in "overdrive" when in top so will never hit the limiter. Some say they can go faster in 5th than 6th...

Up one on the front and/or 3 on the front, then you'll probably be able to get closer to it.

.

[CSpronken]

Originally Posted by 2mths

The wind resistance is proportional to the square of your speed, so getting another mph requires a a chunk more power (or less resistance). I don't see when you could expect to use this additional speed anyway.

In fact wind resistance increase to the power 3 of speed, but because you obviously also cover more distance per second fuel consumption expressed per distance only increases as the square of the speed (more or less).

Originally Posted by gettin2dizzy

My bike does 120 at 9000 in 6th. You got standard gearing?

Perhaps he's got a 16 front sprocket? Are you the first owner of the bike? EDIT: BTW If that's 120 mph on the dash, that would be about 112 mph and then little over 9000 would be quite normal, so then it might be a power issue or perhaps circumstances like headwind or slight slope.

Originally Posted by Jelster

Gear it down... You're basically in "overdrive" when in top so will never hit the limiter. Some say they can go faster in 5th than 6th...

My curvy's 6th certainly is no overdrive, I pass max. power revolutions before reaching top speed (although power does not decrease much passed 9000 RPM on most powercurves I've seen).

Originally Posted by CSpronken

In fact wind resistance increase to the power 3 of speed, but because you obviously also cover more distance per second fuel consumption expressed per distance only increases as the square of the speed (more or less).

Sorry but I think you're talking sh1te there.

Drag force = (d * V^2 * Cx * S) / 2

Where:
d = air density
V = velocity
Cx = Drag coefficient
S = Frontal surface area

or http://en.wikipedia.org/wiki/Drag_%28physics%29

[CSpronken]

Originally Posted by 2mths

Sorry but I think you're talking sh1te there.

Drag force = (d * V^2 * Cx * S) / 2

Where:
d = air density
V = velocity
Cx = Drag coefficient
S = Frontal surface area

or http://en.wikipedia.org/wiki/Drag_%28physics%29

Well we are are both wrong, but still you need engine power to the power of 3, look one chapter down on that same wikipedia page:

Power

The power required to overcome the aerodynamic drag is given by:
Note that the power needed to push an object through a fluid increases as the cube of the velocity. A car cruising on a highway at 50 mph (80 km/h) may require only 10 horsepower (7.5 kW) to overcome air drag, but that same car at 100 mph (160 km/h) requires 80 hp (60 kW). With a doubling of speed the drag (force) quadruples per the formula. Exerting four times the force over a fixed distance produces four times as much work. At twice the speed the work (resulting in displacement over a fixed distance) is done twice as fast. Since power is the rate of doing work, four times a work in half the time requires eight times the power.
It should be emphasized here that the drag equation is an approximation, and does not necessarily give a close approximation in every instance. Thus one should be careful when making assumptions using these equations.

I don't think anything I said was actually wrong (though if I'd gone on to say more it probably would have been). So in the spirit of things...

I'll offer you a draw?